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August 14, 2012 2:00pm UTC

Number of degrees of freedom solved for: 96195

Dear Sirs,

I am trying to understand from where the number 96195 comes from.

In particular, the mesh I am considering is a tetraedral mesh of a rectangular domain in 3D ( width = 5 cm, depth = 1.5 cm, height = 0.35 cm). The mesh, according to the mesh statistics the domain discretization is made of:

Prism elements: 6600
Triangular elements: 264
Quadrilateral elements: 1900
Edge elements: 276
Vertex elements: 8

I am using nearly-incompressible model for the material, there a mixed formulation is used to solve the problem and the pressure field is computed (which is not specified but since I use quadratic polynomial functions, it could be P1).
According to the formula presented in www.comsol.com/support/knowledgebase/875/ the number of nodes should be 6600*1.4 = 9240 and the DOFs (for the displacement) = 9240*3 = 27720. Adding the DOFf for the pressure (which is P1) we do not get 96195.

As someone an explanation for the number of DOF???

Many thanks,

Paolo

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August 16, 2012 8:21am UTC in response to Ivar Kjelberg

Re: Number of degrees of freedom solved for: 96195

Many thanks!

Have a nice day.

Paolo.

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