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November 3, 2012 11:31am UTC

Angle of incidence, RF modul, Comsol 4.2a

Dear All,

I have issue. I have one metal block on substrate, and I want to illuminate it but at some angle (picture).

One half sphere is substrate, one half air.

Now I want to apply x polarization, scattered field.


I have two cases, first when substrate is also air, and second when substrate is glass (with index refraction ns).

In the case when substrate is air I applied equation: E0*exp(-j*(emw.k0*x*sin(phi)+emw.k0*z*cos(phi)).

In the case when substrate is glass I applied equation: E0*exp(-j*(emw.k*x*sin(phi)+emw.k*z*cos(phi)).


Or maybe in second case I have to write:

(1-sign(z))*E0*(-j*2*pi*x*sin(phi)/Lambda-j*2*pi*z*cos(phi)/Lambda)/2 +

+ (1+sign(z))*E0*(-j*2*pi*x*sin(phi)*ns/Lambda-j*2*pi*z*cos(phi)*ns/Lambda)/2


Tell me please for any of these equations are they correct.


Thank very much in advanced.

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November 17, 2012 4:53pm UTC in response to

Re: Angle of incidence, RF modul, Comsol 4.2a

I used scattering boundary condition, but I am nor sure that I understoood second question about equation.

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November 18, 2012 2:42pm UTC in response to Yuanpeng Wu

Re: Angle of incidence, RF modul, Comsol 4.2a

Hello,

I am not sure about second way. I used first way: E0*exp(-j*(emw.k0*x*sin(phi)+emw.k0*z*cos(phi)). I always use incidetn field, not wave direction.

Cheers

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