April 7, 2013 7:35pm UTC
sorry the continuous questions today! I am going to use symmetry for the geometry as in the picture I attached. The simplified geometry is a multilayer (only the green part) composed of layers of different materials and thickness, and four strips A (=C) and B (=D) jointed on top and at the bottom of it.
For time calculation reducing (I have to deal with a more complex structure), I would use symmetry, as A=C and B=D, with a plane of symmetry in the middle of the multilayer. Therefore, I would consider only A and B in the calculation, for example.
But I can't use Symmetry, as it is required a face in the middle plane of the multilayer, but the multilayer is not Symmetric! I should need something like a plane recognized by the function Symmetry, and not a physical surface.
Thank you in advance
April 8, 2013 5:05am UTC in response to Fabio Greco
to apply symmetry you need that all items are "symmetric" so if you thickness of the central multilayer are not symmetric, you will get some discrepancies if you apply a symmetry plane at mid "middle Layer" indeed
Now you might be able to apply "symmetry" for half the length, it's already something
April 8, 2013 8:35am UTC in response to Ivar Kjelberg
thank you for your reply (always satisfactory!). In conclusion, I can't use symmetry in my case. What other solutions are available to reduce the time calculation, in the particular case of my model?
Furthermore, is it worth suggesting to COMSOL support to modify the symmetry function for the next releases, in order to take into account parts not in contact with the middle plane? Thus, something already present in the function Mirror (Geometry), where you can define the plane of reflection...
April 8, 2013 9:13am UTC in response to Fabio Greco
but I believe that is rather tricky, you can do it now but you need to write out the equations, and I'm not sure your demand can be made generic, and COMSOL so far has only proposed generic BC's that apply (almost) for any situation)
October 31, 2013 11:04am UTC in response to Ivar Kjelberg
I have been using the symmetry boundary condition for structural mechanics. Now that I see the results, I realize that the symmetry condition in Structural Mechanics only forces the normal displacements to the symmetry surface to be zero (n·u = 0), but not the rotations. The result is that the deformed geometry has no continuity in symmetry plane.
Would you know how to force rotations to be zero as well? Is it normal that the symmetry condition does not acocunt for that already?
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