# Discussion Forum

## electric field and potential distribution

 Topics: 4.3, AC/DC Module
RSS feed   |   Turn on email notifications   |   5 Replies   Last post: May 8, 2013 2:09pm UTC

N Murugan

May 7, 2013 9:23am UTC

electric field and potential distribution

Hi

I have been working on a 3D (AC/DC) model of a insulator, and I am trying to verify the uniform potential and field distribution along the insulator surface.

I apply 33Kv voltage at HV end. I got result, in this result potential along the insulator surface is uniform distribution, i want field also uniform distribution along the surface.

Edgar J. Kaiser
Certified Consultant
emPhys Physical Technology

May 7, 2013 9:34am UTC in response to N Murugan

Re: electric field and potential distribution

Hi,

the field is the gradient of the potential. So your request is not physical. A uniform potential gives zero field. A linear potential distribution gives a uniform field.

Cheers
Edgar
--
Edgar J. Kaiser
www.emphys.com

N Murugan

May 7, 2013 4:57pm UTC in response to Edgar J. Kaiser

Re: electric field and potential distribution

Thank u sir

I apply 33Kv voltage at HV end. I got result, in this result potential along the insulator surface is linear distribution, but not uniform field distribution along the surface and also field at HV (33KV) terminal as same as ground terminal, why sir ?
i attach my model image.

Edgar J. Kaiser
Certified Consultant
emPhys Physical Technology

May 7, 2013 7:08pm UTC in response to N Murugan

Re: electric field and potential distribution

I would expect a higher field close to the terminals and the geometry is the same on both ends.

--
Edgar J. Kaiser
www.emphys.com

N Murugan

May 8, 2013 1:02pm UTC in response to Edgar J. Kaiser

Re: electric field and potential distribution

Hi

In HV end : field is high bcoz 33Kv applied, but same field will occur in ground end (zero potential), why sir?

Edgar J. Kaiser
Certified Consultant
emPhys Physical Technology

May 8, 2013 2:09pm UTC in response to N Murugan

Re: electric field and potential distribution

Sure, your geometry is symmetric. It doesn't matter where HV and ground are connected.

But looking at your pictures, I think you are making a very basic mistake. You don't have an air volume around your device. So you confine the model into the interior of the device. That is probably not what you want.

Another hint: The device has axial symmetry. You can save tremendous memory and computing time by setting up this in 2Daxial geometry. And the precision of the results can be much better.

Cheers
Edgar

--
Edgar J. Kaiser
www.emphys.com

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