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Number of degrees of freedom solved for: 96195
Posted Aug 14, 2012, 10:00 AM EDT Structural Mechanics & Thermal Stresses Version 4.2a 2 Replies
I am trying to understand from where the number 96195 comes from.
In particular, the mesh I am considering is a tetraedral mesh of a rectangular domain in 3D ( width = 5 cm, depth = 1.5 cm, height = 0.35 cm). The mesh, according to the mesh statistics the domain discretization is made of:
Prism elements: 6600
Triangular elements: 264
Quadrilateral elements: 1900
Edge elements: 276
Vertex elements: 8
I am using nearly-incompressible model for the material, there a mixed formulation is used to solve the problem and the pressure field is computed (which is not specified but since I use quadratic polynomial functions, it could be P1).
According to the formula presented in www.comsol.com/support/knowledgebase/875/ the number of nodes should be 6600*1.4 = 9240 and the DOFs (for the displacement) = 9240*3 = 27720. Adding the DOFf for the pressure (which is P1) we do not get 96195.
As someone an explanation for the number of DOF???