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How to use AC excitation?

Hello, my name is Wang Jiujiang from University of Macau.
I am using COMSOL to simulate a capacitor, after I simulated
using DC voltage, I want to add AC voltage.

After I add a physics--circuit and then 'voltage source', I cann't
add the source to the driving voltage of capacitor.

Can anyone give me some hints for this problem?

Thanks !

Wang Jiujiang

6 Replies Last Post Jan 21, 2013, 12:55 AM EST
Posted: 5 years ago Jan 11, 2013, 3:10 AM EST
Hi,

use a frequency domain study! This equals an AC exciatation.
Hi, use a frequency domain study! This equals an AC exciatation.

Posted: 5 years ago Jan 13, 2013, 10:08 PM EST
Thanks! Eric!

I'll try.
Thanks! Eric! I'll try.

Posted: 5 years ago Jan 17, 2013, 10:35 PM EST

Hi,

use a frequency domain study! This equals an AC exciatation.



Maybe there is something wrong in my model, I am still trying. >>>>>>>>
[QUOTE] Hi, use a frequency domain study! This equals an AC exciatation. [/QUOTE] Maybe there is something wrong in my model, I am still trying. >>>>>>>>

Posted: 5 years ago Jan 18, 2013, 3:28 AM EST
Can you provide an equation of your excitation voltage?

Is it purely AC like u(t)=u_0*sin(2*pi*t/T)

or DC superposed with AC like u(t)=u_DC+u_0*sin(2*pi*t/T)
Can you provide an equation of your excitation voltage? Is it purely AC like u(t)=u_0*sin(2*pi*t/T) or DC superposed with AC like u(t)=u_DC+u_0*sin(2*pi*t/T)

Posted: 5 years ago Jan 18, 2013, 9:10 PM EST
Thanks for you answer.

I'll try it in Monday.

Happy weekend!

Wang Jiujiang
Thanks for you answer. I'll try it in Monday. Happy weekend! Wang Jiujiang

Posted: 5 years ago Jan 21, 2013, 12:55 AM EST

Can you provide an equation of your excitation voltage?

Is it purely AC like u(t)=u_0*sin(2*pi*t/T)

or DC superposed with AC like u(t)=u_DC+u_0*sin(2*pi*t/T)


Hello, Eric:

Thanks very much!

Just as you told me. I can add AC signal now!
[QUOTE] Can you provide an equation of your excitation voltage? Is it purely AC like u(t)=u_0*sin(2*pi*t/T) or DC superposed with AC like u(t)=u_DC+u_0*sin(2*pi*t/T) [/QUOTE] Hello, Eric: Thanks very much! Just as you told me. I can add AC signal now!

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