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I need to find current in Amperes from current density A/m^2

Posted Dec 29, 2020, 2:25 p.m. EST Electromagnetics, Low-Frequency Electromagnetics, Semiconductor Devices 1 Reply

Shahvaiz Khan
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I am working with thermoelectric generator and I have applied temprature difference on top and side and bottom side of ceramic plates. After I solve, I get the electric potential and current density but I am interested in Current in Amperes and not in Amperes / m^2. Can anyone help?

1 Reply Last Post Dec 29, 2020, 2:38 p.m. EST
Robert Koslover Certified Consultant
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Posted: 5 years ago Dec 29, 2020, 2:38 p.m. EST

You need to integrate your current density across a cross-sectional surface (presumably one normal to it). There are a number of ways to do that. If you don't already have that surface defined in your problem, you can add a 3D cut-plane. You can do such integrals post-solving. Go to Results --> Derived Values, right-click on that and choose Integration, then Surface Integration, then choose Cut Plane 1 from the Dataset pulldown under Data in the Settings panel. Alternatively, you can also set up Probes that integrate quantities of interest over various surfaces that you specify.

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Scientific Applications & Research Associates (SARA) Inc.
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You need to integrate your current density across a cross-sectional surface (presumably one normal to it). There are a number of ways to do that. If you don't already have that surface defined in your problem, you can add a 3D cut-plane. You can do such integrals post-solving. Go to Results --> Derived Values, right-click on that and choose Integration, then Surface Integration, then choose Cut Plane 1 from the Dataset pulldown under Data in the Settings panel. Alternatively, you can also set up Probes that integrate quantities of interest over various surfaces that you specify.

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