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How to get the derivative of stress along r direction in 2-D axisymmetric model
Posted Apr 7, 2015, 6:38 p.m. EDT Structural Mechanics Version 4.4 10 Replies
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However, the 'd(solid.pm,z)' can give me the right distribution of derivative of pressure along the Z axis. as shown in the Figure 2.
Can anybody tell me the reason?
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In axial symmetry, the analytical expression for the strain in the circumferential direction is
When the radius approaches zero (on the z-axis) this expression becomes problematic from the numerical point of view.
So when you take a derivative of the stress, the underlying operation will be to compute the r-derivative of the expression above. This is why you see disturbances close to the z-axis. The result will be very sensitive to the mesh size at small r-coordinates.
In the formulation. we do take measures to avoid zero-divide in the strain itself, but that does not protect against taking derivatives of it.
Regards,
Henrik
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Thanks so much for your explanation. Now I understand why disturbances will appear when close to the z-axis.
As you mentioned, Comsol takes measures to avoid zero-divide in the strain itself in that formulation while does not protect against taking derivatives of it. However, if I want to take derivatives of it, are there any methods to avoid this disturbance? Thanks you!
Best,
Rong
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I would propose split your domain around r=0 i.e. at a r=r_min and have at least 3 elements along the radial direction in this small cercle.
Or just omit the central part at r<r_min from your model. remains to define what walie to put on r_min
--
Good luck
Ivar
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I just realized the major issue here: The derivatives should be taken with respect to to 'R', not 'r'.
A quote from the user's guide:
"From a simulation perspective it is desirable to solve the equations of solid mechanics on a fixed domain, rather than on a domain that changes continuously with the deformation. In COMSOL Multiphysics this is achieved by defining a displacement field for every point in the solid, usually with components u, v, and w. At a given coordinate (X, Y, Z) in the reference configuration (on the left of Figure 2-4) the value of u describes the displacement of the point relative to its original position. Taking derivatives of the displacement with respect to X, Y, and Z enables the definition of a strain tensor, known as the Green-Lagrange strain (or material strain). This strain is defined in the reference or Lagrangian frame, with X, Y, and Z representing the coordinates in this frame. The displacement is considered as a function of the material coordinates (X, Y, Z), but it is not explicitly a function of the spatial coordinates (x, y, z). It is thus only possible to compute derivatives with respect to the material coordinates."
Regards,
Henrik
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Hi Henrik,
Thanks so much. Now I can get right derivatives of stress with respect to R.
However, my problem is the coupling of diffusion and stress. In diffusion part, there is no material deformation. So I cannot get derivatives of concentration with respect to R. If I still used the derivatives of concentration with respect to r while the derivatives of stress with respect to R, I think there mush be some problems. Do you have some advices?
Best,
Rong
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I think your method is a good way to deal with the singularity near the axis. I will try it! Thanks so much.
Best,
Rong
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As long as the deformations are not so large that there is a significant change in the geometry, there should not be any problem in mixing derivatives with respect to 'r' and 'R' as long as you respect the type of dependency that a certain variable has.
If the deformations are large, then several difficult aspects will arise. Some are:
a) the dependence of the diffusivity on strain
b) spatial and material orientations start to differ
Regards,
Henrik
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Hi Henrik,
You are right, thanks so much. Now I can understand it.
Meanwhile, I have another question:
as you said, the derivatives of the deformation should be with respect to the material coordinate X,Y,Z, like d(u,X), d(u,Y). However, in my model, although there is a singularity in calculating d(u,r), I can still get the derivatives of the deformation with respect to the spatial coordinate z.
Moreover, I tried a 3D model and found I can get the derivatives of the deformation with respect to the spatial coordinate x,y, z.
I am a little confused about it. If you said the deformation should be with respect to the material coordinate, What is those derivatives I get? are there any relationship between d(u,x) and d(u,X)? Thanks!
Best,
Rong
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You are right, thanks so much. Now I can understand it.
Meanwhile, I have another question:
as you said, the derivatives of the deformation should be with respect to the material coordinate X,Y,Z, like d(u,X), d(u,Y). However, in my model, although there is a singularity in calculating d(u,r), I can still get the derivatives of the deformation with respect to the spatial coordinate z.
Moreover, I tried a 3D model and found I can get the derivatives of the deformation with respect to the spatial coordinate x,y, z.
I am a little confused about it. If you said the deformation should be with respect to the material coordinate, What is those derivatives I get? are there any relationship between d(u,x) and d(u,X)? Thanks!
Best,
Rong
Hi,
As long as the deformations are not so large that there is a significant change in the geometry, there should not be any problem in mixing derivatives with respect to 'r' and 'R' as long as you respect the type of dependency that a certain variable has.
If the deformations are large, then several difficult aspects will arise. Some are:
a) the dependence of the diffusivity on strain
b) spatial and material orientations start to differ
Regards,
Henrik
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