Discussion Forum

Posted: 1 decade ago Mar 11, 2011, 11:04 a.m. EST

Hi set a work plane on the surface, and draw a circle in there, then make an embedded "surface" It worked in v3.5, haven't tried it yet in v4 -- Good luck Ivar

Posted: 1 decade ago Mar 11, 2011, 11:16 a.m. EST

Hi, In 4.1, the "embedding" is implicit, so all you need to do is to create a work plane that represents the block surface and then draw the circle on that work plane's geometry. Then finalize the geometry (by moving on to the physics settings, for example). The circle then defines a separate surface so that you can specify another boundary condition in that area. See the attached screen shot. Best regards, Magnus Ringh, COMSOL

Attachments:

• embedded_circle.PNG

Posted: 1 decade ago Mar 11, 2011, 11:38 a.m. EST

Excellent! Thank you both.

Posted: 1 decade ago Apr 6, 2011, 4:03 p.m. EDT

Hi, How do you create this work plane on a curved surface, say on a sphere? I want to create a boundary area that is on the surface of a hemisphere. APpreciate any advice, thank you! Austin

Posted: 1 decade ago Apr 7, 2011, 1:52 a.m. EDT

Hi you have different options to define your workplane: the "quick way" see the options, typically along the coordinates, or on a surface, or via a set of points, up to you to define/precise for the programme -- Good luck Ivar

Posted: 1 decade ago Jun 20, 2011, 11:36 a.m. EDT

Hi there I am working with 4.0, I created a work plane and drew a circle, but when I go over to one of the physics, the circle is gone and I cant even assign any physics to the circle. Any clues? thanks! liwah [QUOTE] Hi, In 4.1, the "embedding" is implicit, so all you need to do is to create a work plane that represents the block surface and then draw the circle on that work plane's geometry. Then finalize the geometry (by moving on to the physics settings, for example). The circle then defines a separate surface so that you can specify another boundary condition in that area. See the attached screen shot. Best regards, Magnus Ringh, COMSOL [/QUOTE]

Posted: 9 years ago Oct 13, 2015, 7:09 p.m. EDT

Hi Magnus, Thanks for sharing! I came across this post as I encountered similar problems. I followed the steps and built a circle on the work plane. But when I go Helmholtz Equation (hzeq), the circle on that work plane is not included in the "all domain" selection. I cannot add source value to the circle. Is there any step I miss? How can I solve the problem? I'm using comsol 5.1. Attached is a figure showing the issue. Thanks in advance for your response! Jianshan

Attachments:

• circle_workplane.JPG

Posted: 8 years ago Apr 19, 2016, 11:23 a.m. EDT

Hello Jianshan, A disc is not 3-dimensional, so it does not define a domain in 3D and you can therefore not assign an equation to be solved on a 3D domain to it. In 3D, you could use a disc to assign a boundary condition, or a PDE defined on a surface, etc. Best, Jeff

Posted: 8 years ago Apr 19, 2016, 11:46 a.m. EDT

Hi Austin, In that case you do not use a work plane: work planes are by definition planes, they cannot be curved. Instead, what you do is that you create a 3-dimensional object that intersects with the curved surface so that their intersection creates the shape you need, as shown in the attached toy model. Best, Jeff

Attachments:

• ForAustin.mph

Posted: 7 years ago Apr 21, 2017, 1:55 a.m. EDT

@Jeff Hiller. Thank you for your responses to questions, years after. And also providing examples. This is the second time your response has been a help.